【暑假班】C1-第5课:顺序结构与数位问题

# 用户名 取最后两位 取月份 取年份 输出倒序数1 取小数数位 已知数位求数2 一个数与它的倒序数之差 三位数 总分
1
C2024021 (陈正言) 100
00:32:32
100
00:35:15
100
00:35:27
100
00:39:19
100
00:39:58
100
00:45:01
100
00:50:06
100
00:55:51
800
00:55:51
1
C2024013 (黄书豪) 100
01:18:51
100
01:18:59
100
01:19:06
100
01:19:16
100
01:19:23
100
01:19:31
100
01:19:46
100
01:19:38
800
01:19:46
1
C2024019 (易钲耕) 100
01:01:19
100
01:06:13
100
01:07:33
100
01:19:39
100
01:25:36
100
01:40:03
100
01:41:56
100
01:44:51
800
01:44:51
1
C2024032 (汪天皓) 100
01:04:06
100
01:14:53
100
01:18:14
100
01:26:13
100
01:35:54
100
01:41:25
100
01:48:22
100
01:50:50
800
01:50:50
1
C2024025 (黄景晨) 100
00:52:11
100
01:11:05
100
01:08:42
100
01:15:30
100
01:36:07
100
01:41:58
100
01:49:06
100
01:54:37
800
01:54:37
1
C2024039 (谈柯南) 100
01:00:47
100
01:13:54
100
01:38:14
100
01:52:02
100
01:47:15
100
01:43:39
100
02:00:15
100
02:06:56
800
02:06:56
1
C2024027 (毛铭浩) 100
01:00:55
100
01:15:02
100
01:17:34
100
01:31:38
100
01:48:29
100
01:43:51
100
02:01:06
100
02:07:29
800
02:07:29
1
C2024026 (毛梓睿 ) 100
01:02:39
100
01:20:03
100
01:39:35
100
01:52:01
100
01:41:07
100
01:44:34
100
02:00:14
100
02:09:10
800
02:09:10
1
C2024024 () 100
01:00:27
100
01:16:24
100
01:38:46
100
01:53:12
100
01:48:00
100
01:44:42
100
02:00:19
100
02:12:07
800
02:12:07
1
C2024014 (李鸿薇) 100
252:51:39
100
252:53:22
100
252:53:36
100
252:53:51
100
252:54:01
100
252:54:08
100
252:54:15
100
252:54:22
800
252:54:22
11
C2024040 (徐艺瑄) 100
01:25:34
100
01:25:34